Time & Distance - Lesson plan #1

Math > 8th Grade > Free Lesson Plans > Time and Distance

 Math
  - math concepts
  - math subjects
  - by grade level
 Math Help
  - Math Tutoring
 Math Games
  - math Games
 Math Worksheets
 - math lesson plans
 - math worksheets
 Math Books
  - used Textbooks
  - math Book SEARCH
 Resources
  - Math websites
  - The Math Forum

Eighth Grade - Time and Distance

Lesson plan #1...

 8th grade time and distance...(please print out)

    Problem:

          On a trip to the mountains lori drove a rate of 55 mph on the trip back home she decided to try a route that was 10 miles shorter as it turn out she took an extra hour to get home an average only 40 miles per hour. find the total distance she traveled. - from Math Help group.

    Solution:

This is a distance, time, speed problem using the equation
distance = speed * time or D = S * T
We have two unknowns, distance and time, but we have information to relate the two. If we let Tm be the time it takes to get to the mountains and Tb be the time to get back from the mountains then we can say that
EQ1: Tb = Tm + 1 (she took an extra hour to get home)
and if we let Dm be the distance to the mountains and Db the distance back from the mountains we have
EQ2: Dm = Db + 10
(a route that was 10 miles shorter)

The only other information we have are the speeds 55mph and 40mph and with these and
D = S * T, we can change EQ1 into EQ2 or vice versa to eliminate one of our unknowns.
EQ2 becomes 55mph * Tm = 40mph * Tb + 10 miles (using D = S * T)
and using EQ1 we have
55mph * Tm = 40mph * (Tm + 1hr) + 10 miles (eliminate Tb)
55mph * Tm = 40mph * Tm + 40 mph * 1hr + 10 miles (now solve for Tm)
55mph * Tm = 40mph * Tm + 40 miles + 10 miles
55mph * Tm - 40mph * Tm = 50 miles
15mph * Tm = 50 miles
Tm = 50 miles / 15 mph
Tm = 10 miles / 3 mph = (10/3) hours = 3 hours and 20 mins.
substituting this into EQ1 we have
Tb = 4 hours and 20 minutes = 13/3 hours
now the total distance she travelled is Dm + Db and since we have both times available and both speeds we have
Dm = 55mph * (10/3) hours = 183 1/3 miles (using D = S * T again)
Db = 40mph * (13/3) hours = 173 1/3 miles
Dm + Db = 356 2/3 miles.

So, the answer is 356 2/3 miles. (356.6 miles) Sometimes, making a table to organize the information from the problem statement can help

Distance Speed Time
To Dm 55 mph Tm
Back Db = Dm - 10 40 mph Tb = Tm + 1hr

 

about us | site index | contact | ...other math links

K12math.com copyright 2005