Complex Numbers


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Complex Numbers


 

A complex number is a number that has two separate components, the first is a real number and the second is also a real number with the letter 'i' appended to it. (the letter 'j' is used in Physics and particularly Electrical Engineering.)



Definition: a complex number has the form (a + bi), where i =


Examples:

 

12 + 3i

 - 4.5 + 6.1i

 3.1

5.32i


The last two examples have one of their components missing; 3.1 is missing the second component, and 5.32 is missing the first component. These numbers are still complex numbers and can be written as (3.1 + 0i) and (0 + 5.3i)


The square root function has the domain non-negative Reals. Since negative numbers are not in this domain, by the limitation imposed by this domain, we simply do not apply the square root to negative numbers. It's common to hear that the square root of a negative number does not exist, but oftentimes in mathematics we extend the concept of a number by adding components, in this case a single component, to get over these limitations, and the square root of negative numbers in particular. (for example, Friederich Gauss proved that all the solutions, zeroes,  of all polynomial equations are complex numbers.)



Geometric interpretation:


The complex number is a convenient way to name a unique point in the XY coordinate system. Given the complex number (a + bi), (a) is the x coordinate, and (bi) is the y coordinate of the point in the plane. So (a + bi) is equivalent to (x,y). In the first case we have a number, in the second a coordinate pair. The complex number allows us to think of the point in terms of a single number rather than a coordinate pair; this number is actually a vector.


Final Note on Naming:


Often you will here the word imaginary used for these numbers. We use the Real numbers without a second thought. The Pythagoreans could not accept the fact that a right triangle whose legs were both 1 gave a hypotenuse with a length (we know to be ) that did not exist in their concept of a number.  However they could demonstrate that some number must exist to represent this length. Unfortunately the term imaginary was used for complex numbers since their definition, but they do model certain phenomena as do all the other numbers. So in this sense they are anything but imaginary. The word complex is somewhat a misnomer as well, since other number definitions are more complex to this one.



Now using the property and the definition for i

we have:


Example:

5i · 6i = 30 · i ·i = 30 · i2 = -30










Operations with complex numbers:


Addition/Subtraction:

  1. Add/Subtract the respective components.

example: 2 + 7i + 3 + 6i = (2 + 3) + (7i + 6i) = 5 + 13i

example: 6 + 14i – (4 + 5i) = 6 – 4 + (14i – 5i) = 2 + 9i

example: -4.2 – 1.2i – ( - 6.1 – 2i ) = -4.2 + 6.1 – 1.2i + 2i = 1.9 + 0.8i


In the last two examples the – sign must be distributed across the parenthesis.


Multiplication:

  1. Treat the complex numbers as binomials and multiply accordingly using the fact the i2 = -1.

example:

(2 + 3i) ( 4 + 6i) = 2(4 + 6i) + 3i(4 + 6i)

= 2 · 4 + 2 · 6i + 3 · 4i + 3i · 6i

= 8 + 12i + 12i + 18i2

= 8 + 24i + 18( -1)

= 8 18 + 24i

=  -10 + 24i

 

Division:


some examples:


explanation:











Now the case :


The problem here is the 'di' in the denominator. It needs to be eliminated.


If we multiply (c + di) by (c - di) we get


c2 - (di)2 = c2 - d2i2 = c2 - d2(-1) = c2 + d2


Notice this eliminates 'i' from the the starting expression, c + di.


The multiplier (c - di) is called the complex conjugate, or more briefly,

the conjugate of (c + di).



Given a complex number, change the sign of the 'i' term and you have its conjugate.


examples:

complex number

its conjugate

3 + 6i

3 - 61

-4 + 10i

-4 - 10i

13 – 12i

13 + 12i

+16i

16i

2

2


Now, back to



Recall that we can multiply any non-zero expression by another (which represents 1) and only change the way it appears, not its value.

32 and 128/4 look different but represent the same value, 32.


If we multiple both the numerator and the denominator by the conjugate of the denominator (c - di) we get:



If you can remember this formula, then it does make this work easier. The first few examples use this formula, the remainder do not. You need to write the denominator and numerator in terms of the original involving addition only first.


Visually it is easy to remember. Add the products vertically, subtract the cross products. The example will illustrate.

Example:



Example:





Powers of i.


power

value

i0

1

i1

i

i2

-1 (i)(i) = -1

i3

-i (i)(i)(i) = -1(i)

i4

1 (i)(i)(i)(i) = -1(-1) = 1

i5

i (i)(i)(i)(i)(i) = -1(-1) i = i

i6

-1 etc...

i7

-i

i8

1

in

depends on n, note the previous examples


odd powers yield (+/-) i, even powers yield (+/-) 1


First determine if n is even or odd. Then ask yourself how many pairs of i do you have as factors. Then you will have your answer.


    examples:


i13 n = 13 is odd, so we have either i or -i as the answer,


i13 = i i12 now, 12/2 = 6, even factors of i2 (= -1)

(-1)(-1)(-1)(-1)(-1)(-1) = 1

i13 = i



i30 n = 30 is even so we will have either 1 or -1 as the answer

30 / 2 = 15, odd number of i2 factors so

i30 = -1


i91 n = 91 is odd, i91 = i i90 and 90/2 = 45 which is


odd, so we have an odd number of i2 factors so


i91 = -i


NOTICE that in all odd cases I first factored a single i out and looked at the exponent of the remaining factor to determine the sign of the result.



 


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